The temperature of a gas is T K. Calculate the
final temperature in which the volume is get
halved of initial and pressure reduced to 1/4th of
initial.
8 T1
T1
8
16 T1
T1/16
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Answer:
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Answered by
0
Answer:
Ideal gas equation, for an adiabatic process is
PV
γ
= constant or P
1
V
1
γ
=P
2
V
2
γ
For monoatomic gas γ=
3
5
P
1
V
1
5/3
=P
2
(
8
V
1
)
5/3
⇒P
2
=P
1
×(2)
5
=32P
1
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