Question

the temperature of a given mass of a gas is increased from 19 degree Celsius to 20 degree Celsius at constant pressure the volume V of the gas is increased​

Answer 1

Answer:

293/292 times

Explanation:

at constant pressure

V=kt

V/xV = 19+273/20+273 1°C = 273K

x= 293/292 times

Answer 2

Dear Student,

◆ Answer -

Increase in volume by V/292.

● Explaination -

# Given -

T = 19 ℃ = 273 + 19 = 292 K

T' = 20 ℃ = 273 + 20 = 293 K

# Solution -

According to Charles law,

V/V' = T/T'

V' = V × T'/T

V' = V × 293/292

V' = 293V/292

Increase in volume is -

∆V =V' - V

∆V = 293V/292 - V

∆V = V/292

Therefore, volume of the gas will increase by V/292.

Thanks dear...