Question

The temperature of a given mass of air was reduced from 15°C to -15° C. If the initial
volume of air was 100ml, what would be its new volume if pressure is maintained a
constant? pls answer​

Answer 1

Answer:

By the relation:

V1 by T1 = V2 by T2

100 ÷ 288 = V2 ÷ 258

V2 = 100*258÷ 288

(here 288 and 258 is the temperature in kelvin ..... we put the temperature in kelvin while calculating)

= 89.5

hope it helps

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Answer 2

Here is ur answer ⬇

P1 and P2 is constant

T1 = 15 + 273 = 288K

T2 = -15 + 273 = 258K

V1 = 100 ml

V2 = ?

P1xV1/T1 = P2xV2/T2

∴ V1/T1 = V2/T2

100/288 = V2/258

100x258/288 = V2

25800/288 =V2

∴ V2 = 89.583 ml

∴ V2 = 89.6 ml

Hope it helps U !