Physics, asked by samparna, 1 year ago

the temperature of a piece of metal is raised from 27°c to 51°c .the rate at which metal radiates energy increases nearly​

Answers

Answered by abhi178
4

according to Stefan's law radiation energy is directly proportional to (temperature)⁴

i.e., E\propto T^4

or, E = kT⁴ , here k is proportionality constant.

initially, T = 27° C = 27 + 273 = 300K

so, E_i = k(300)⁴ = 81 × 10^8 k

finally, T = 51°C = 51 + 273 = 324K

so, E_f = k(324)⁴ = 110.2 × 10^8 k

change in energy , ∆E = (110.2 - 81) × 10^8 k = 29.2 × 10^8k

percentage increases in energy = 29.2 × 10^8k/81 × 10^8k × 100

= (2920)/81

= 36.04 %


samparna: thnx a lot yrr
abhi178: My pleasure :)
samparna: hmm
Answered by Anonymous
1

Answer:

          36.04 %

Explanation:

E = kT⁴ , here k is proportionality constant.

initially, T = 27° C = 27 + 273 = 300K

so,  = k(300)⁴ = 81 × 10^8 k

finally, T = 51°C = 51 + 273 = 324K

so,  = k(324)⁴ = 110.2 × 10^8 k

change in energy , ∆E = (110.2 - 81) × 10^8 k = 29.2 × 10^8k

percentage increases in energy = 29.2 × 10^8k/81 × 10^8k × 100

= (2920)/81

= 36.04 %

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