Question

The temperature of a place at 12 noon was 14°C. If it decreased by 3°C each hour,What was the temperature at 8 p.m?

Answer 1

Answer:

Hii dear here is your answer

Step-by-step explanation:

Solution :-

At 12 noon, the temperature = 10° C above zero

The temperature is decreasing at 2° C per hour

8° C below zero = - 8° C

So, total fall in temperature from 10° C to 0° C and from 0° C to - 8° C = 18° C

Since the temperature falls 2° C in every one hour.

Therefore, to decrease 18° C, time taken = 18/2

= 9 hours

Present time is 12 noon so, the time when the temperature is - 8° C

= 12 noon + 9 hours

So, The time at which the temperature will be - 8° C = 9 PM

At 9 PM, the temperature is - 8° C, the temperature at 12 midnight will be = 

(- 8° C) + (- 2° C × 3 hours)

= (- 8° C) + (- 6° C)

= - 14° C

So, at 12 midnight the temperature will be - 14° C.

Answer 2

Answer:

temperature at 12 noon  is 14

as the temperature is decreasing by 3 degrees every hour then it means -3 per hour

temperature at 8 pm = after 8 hours

-3 x 8 + 14= -14 degree celsius