the temperature of certain volume of gas at 15 atm is 127 C. if the pressure is raised to 30 atm then wht will be the temperature for that gas.
plz answer
Answers
Answered by
0
Answer
Correct option is
A
−123
0
C
We know that
T
1
P
1
V
1
=
T
2
P
2
V
2
∴ T
2
=
P
1
V
1
P
2
V
2
T
1
Here, P
1
= 30 atm, P
2
= 1 atm, V
1
= V (say), V
2
= 15 V,
T
1
=27
o
C = 27 + 273 = 300
o
K and T
2
= ?
substituting these values, we get T
2
=150
o
K
∴ T
2
=150
o
K = 150−273 = −123
o
K
Answered by
0
Answer:
We know that T1P1V1=T2P2V2
∴ T2=P1V1P2V2T1
Here, P1 = 30 atm, P2 = 1 atm, V1 = V (say), V2 = 15 V,
T1=27oC = 27 + 273 = 300oK and T2 = ?
substituting these values, we get T2=150oK
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