Question

The temperature of gas is increased to 9 times. What is the ratio of the new RMS velocity to the old RMS velocity ? plzz give and fast.​

Answer 1

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• Given :

=> the temperature of a gas is increased by 9 times

• To Find :

=> ratio of new RMS velocity and old RMS velocity

• Formula :

=> RMS velocity of a gas is given by

$\boxed{ \sf{ \pink{ \bold{v \tiny{rms} = \sqrt{ \frac{3 \times K \tiny{b} \times T}{m} }}}}} \\ \\ \therefore \boxed{ \bold{ \sf{ \pink{v \tiny{rms} \propto \: \sqrt{T} }}}}$

• Calculation :

$\implies \sf \: \frac{v \tiny{rms}1}{v \tiny{rms}2} = \sqrt{ \frac{T1}{T2} } = \sqrt{ \frac{1}{9} } = \frac{1}{3} \\ \\ \implies \sf \orange{\boxed{ \red{ \bold{ \huge{v }\tiny{rms}2 = \huge{3v} \tiny{rms}1 }}}}$

Answer 2

Hey sorry I don't know....