the temperature of ideal gas is increased from 120K to 480K.if at 120K the root mean square velocity of the gas molecule is V then what will be the root mean square velocity at 480K?
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Answer:
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Explanation:
ANSWER
v
2
v
1
=
M
3RT
2
M
3RT
1
=
T
2
T
1
∴v
2
=2v
1
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