The temperature of liquid is -5 degree C. The liquid boils at 70 degrees. The temperature of the liquid rises @ 5 degrees/min. After how much time does the liquid start boiling? Please Explain in detail.
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Answered by
0
Initial temperature = -5°C
Temperature to be attained = 70°C
So, temp. difference = 70 - (-5) = 75°C
Rate = 5°C/min
So, time reqd. = 75/5 = 15°C
Temperature to be attained = 70°C
So, temp. difference = 70 - (-5) = 75°C
Rate = 5°C/min
So, time reqd. = 75/5 = 15°C
Answered by
1
Starting(Initial) temperature of liquid = -5ºC
The temperature to be attain for liquid = 70ºC
The temperature difference = 70-(-5) = 75
Rate of Boiling = 5º/min
The liquid starts boiling = 75/5 = 15
So, the answer is 15ºC
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