The temperature of sink of heat engine is 27 degree c and its efficiency is 40 % what will be the temperature of source
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Explanation:
★ EFFICIENCY ( E )
» SINK TEMPERATURE ( T² ) = 27°C = 300 K
» SOURCE TEMPERATURE ( T¹ ) = ???
» EFFICIENCY = 40 %
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★ EFFICIENCY = [ 1 - T² / T¹ ] ★
» E = 1 - 300 / T¹
» 0.4 = 1 - 300 / T¹
» 0.4 = T¹ - 300 / T¹
» 0.4 T¹ = T¹ - 300
» 0.6 T¹ = 300
» T¹ = 300 / 0.6 = 500 K
★ TEMPERATURE OF SOURCE ( T¹ ) = 500 K ★
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