The temperature of the gas is raised from 27°C to
927°C, the root mean square velocity is
(a)√927 / 27 time the earlier value
(b) same as before
(c) halved
(d) doubled
Answers
Answered by
0
Explanation:
options d
not sure about the answers
Answered by
3
(d) doubled
Explanation:
Given:
T1 = 27°C = 300 K
T2 = 927°C = 1200 K
We know that root mean square velocity, v ∝ √T.
Therefore, root mean square velocity of the gas when its temperature is raised = √T₂/T₁
= √1200/300
= √4
= 2
Hence option D is the correct answer.
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