Question

The temperature of the sink of a Carnot engine is 300 K and its efficiency is 40%. Find the decrease in temperature of the sink required to increase the efficiency of the engine to 50% keeping temperature of the source to be constant.

Answer 1

Answer: 250K

Explanation:

Answer 2

Answer

Decrease in temperature is T₂ = 250 K

Explanation:

We have been given

Sink temperature is T₁ = 300 K

Efficiency  40%

Now

Carnot Efficiency = 1 - $\dfrac{sink \\temperature}{source \\temperature}$

$\dfrac{40}{100}= 1-\dfrac{300}{T}$

Source temperature T₂ = 500 K

Therefore,

Efficiency of the engine 50 %

Now

$\dfrac{50}{100} =1-\dfrac{T}{500}$

Decrease in temperature is T₂ = 250 K

Correct answer in Decrease in temperature is T₂ = 250 K