the temperature T1 and T2 of the two heat reservoir in a ideal carnot engine be 1500°C and 500°C respectively. which of the there increasing T1 by 100°C or decreasing T2 by 100°C would result in a greater improvement in the efficiency of heat engine
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Answered by
1
Answer:
efficiency=(t1-t2)/t1
Explanation:
because if you increase the value of t1 ,the denominator will also rise,so reducing t2 by 100 will give you more efficiency.
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Answered by
2
Answer:
And the answer is here..
Explanation:
Therefore decreasing T2 by 100°c would result in greater improvement in the efficiency of heat engine..
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