The temperatures of two bodies A and B are
respectively 727°C and 327°C. The ratio HA:Hg of
the rates of heat radiated by them is
(a) 727: 327
(b) 5:3
(c) 25:9
(d) 625:81
Answers
Answered by
7
Explanation:
as per Stefan Boltzmanns law heat radiated by a body is proportional to 4th power of its absolute temperature.
for body A Ta = 727℃ = 1000 °k
for body B Tb = 327 ℃= 600 °k
therefore Ha/Hb = (Ta^4)/(Tb^4)
= (1000^4)/(600^4)
= 7.716:1
but from option, last option d i.e 625:81 matches exactly with the answer obtained above.
Answered by
1
Answer:
625:81
Explanation:
for body A Ta = 727℃ = 1000 °k
for body B Tb = 327 ℃= 600 °k
therefore Ha/Hb = (Ta^4)/(Tb^4)
= (1000^4)/(600^4)
= 7.716:1
but from option, last option d i.e 625:81 matches exactly with the answer obtained above.
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