Question

The temperatures of two bodies measured by a thermometer are t₁ = 20ᵒC ± 0.5ᵒC and t₂ = 50ᵒC ± 0.5ᵒC. The temperature difference t = t₂ – t₁ between them is given by
(a) t = 30ᵒC ± 0.5ᵒC
(b) t = 70ᵒC ± 0.5ᵒC
(c) t = 70ᵒC ± 1.0ᵒC
(d) t = 30ᵒC ± 1.0ᵒC​

Answer 1

Here, t₁ = 20°C +0.5°C

t₂ = 50°C + 0.5°C

The temperature difference between the two bodies is

t = t₂ - t₁

= 50°C - 20°C = 30°C

The error in temperature difference is given by

Δt = (Δt₁ + Δt₂) = (0.5°C +0.5°C) = 1°C

The temperature difference is 30°C + 1°C

Answer 2

Given  : The temperatures of two bodies measured by a thermometer are t₁ = 20ᵒC ± 0.5ᵒC and t₂ = 50ᵒC ± 0.5ᵒC.

To Find : The temperature difference t = t₂ – t₁  

(a) t = 30ᵒC ± 0.5ᵒC

(b) t = 70ᵒC ± 0.5ᵒC

(c) t = 70ᵒC ± 1.0ᵒC

(d) t = 30ᵒC ± 1.0ᵒC​

Explanation:

t₁ =  20ᵒC ± 0.5ᵒC

t₂ = 50ᵒC ± 0.5ᵒC.

temperature difference t = t₂ – t₁  

t = (50 - 20)°C  ± (0.5 +  0.5)°C  

( Errors/Tolerances are always added up , when u add or subtract term ) .

=> t = 30°C  ± 1°C

The temperature difference t = 30°C  ± 1°C

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