Question

The ten digit number 2x600000y8 is exactly divisible by 24. If x ≠ 0 and y ≠ 0, then the least value of (x + y) is equal to:

Answer 1

Answer:

A zoo me zip Kew zoo me pa app new me zip new cycle power boat pow di

Step-by-step explanation:

do ora Spanish well spa do so is so is all Oz do ya DL is DL ya

Answer 2

The least value of (x+y) is 2.

Step-by-step explanation:

Since we have given that

2x600000y8 is divisible by 24

So, it must be divisible by 8 and 3 both

As we know the divisibility of 8,

Last 3 digit must be divisible by 8 :

$0y8=08$ is divisible by 8

So, y =0

Now, for divisibility of 3, the sum of digits must be divisible by 3.

$2+x+6+0+8=x+16=2+16=18$ which is divisible by 3.

So, it becomes,

$x+y=2+0=2$

Hence, the least value of (x+y) is 2.

# learn more:

The ten digit number 2x600000y8 is exactly divisible by 24. If x ≠ 0 and y ≠ 0, then the least value of (x + y) is equal to:a

https://brainly.in/question/16053614