The ten digit of a 2 digit number is 5 more than the unit's digit. When reversed and
added to the original number the answer is 99. Find the original number.
Answers
Answer:72
Step-by-step explanation
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let the units digit be y,
and the tens digit be x.
Thus the number is 10x+y
according to the condition,
(10x+y)-(10y+x) =45
9(x - y)=45
x-y=5.......(1)
also x+y=9...(given)
Adding(1) and (2)
2x=14
x=7
Putting in (1)
y=7-5
y=2
Answer:
Let the tens digit be y and the ones digit be x.
The original number = 10y + x
The reverse number = 10x + y
It is given that ones digit is twice the tens digit :]
➳ x = 2y ............[Equation (i)]
According to question now,
➳ 10x + y + 10y + x = 99
➳ 11x + 11y = 99
➳ 11 (x + y) = 99
➳ x + y = 99/11
➳ x + y = 9
➳ y = 9 - x.........[Equation (ii)]
Now, Substituting equation (ii) in equation (i) we get :
➳ x = 2 (9 - x)
➳ x = 18 - 2x
➳ 3x = 18
➳ x = 18/3
➳ x = 6
Putting x = 6 in equation (ii) we get :
➳ y = 9 - x
➳ y = 9 - 6
➳ y = 3
Therefore,
The original number = 10y + x = 10(3) + 6 = 30 + 6 = 36