Question

the ten digit of a 2 number is less than the ones digit by 3 if the digit are reversed the difference between the two numbers is 27 if the sum of the digit is 11 find the number​

Answer 1

Step-by-step explanation:

Solution

Let the number be 10a+b where a is tens digit and b is ones digit then equation will be

$1)b - a = 3$

$2)(10b + a) - (10a + b) = 27$

$3)a + b = 11$

Notice that (2) simplifies to 9(b−a)=27 which is the same as (1). One of these is redundant.

Adding (1) to (3) we get 2b=14⇒b=7 and so a=4 and the number is 47 .