Question

The ten digit of a two digit number exceed the unit digit by 5.if the number are reversed ,the new no is less by 45.if the sum of their digit is 9 find the no

Answer 1

Let the digit in the units place be x
Hence the digit in the tens place is (x + 5)
The original number = 10(x + 5) + x = 11x + 50
Number formed by reversing the digits = 10x + (x + 5) = 11x + 5
Given that (11x + 50) + (11x + 5) = 99
⇒ 22x + 55 = 99
⇒ 22x = 99 – 55 = 44
⇒ x = 2
Original number = 11x + 50 = 11(2) + 50 = 72
 Hence the original number is 72.

Answer 2

hey here is the answe is 73