Question

the ten digit of a two digit number is 4 times the unit digit.the sum of the number and the unit digit is 42.find the number.​

Answer 1

Answer: the 2 digit no is 41.

Step-by-step explanation:

let the tens digit be = x

let the ones digit be = y

number = 10x +y

10x +y+y=42

10x+2y=42 1

x-4y=0 2

from evaluating 1 and 2 the required number is 41