The ten's digit number is the thrice the unit digit. the new number obtained by interchanging the digit is 54 less than the digital number. find the original number
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QUESTION:
In a two digit number, the ten's digit is three times the unit digit. when the number is decreased by 54, the digits are reversed. find the number.
ANSWER:
Let the digit at unit's place be x.
GIVEN : digit at Ten’s place = 3x
Number formed :
10 × 3x + x = 30x + x = 31x
Number formed after reversing the digits:
10 × x + 3(x )= 10x +3x = 13x
ATQ,
31x -54 = 13x [Given]
31x -13x = 54
18x = 54
x = 54/18
x= 3
Number = 31x = 31 × 3 = 93
Hence, the number is 93.
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