Question

The ten's digit of a number is four times its ones digit. If 27 is subtracted from the number digits of the difference obtained are reverse of those of number. Find the number.​

Answer 1

Answer:

the answer for the given question is the number is 9

Answer 2

Given:-

• The tens digit of a number is four times it's ones digit.
• If 27 is subtracted from the number digits of the difference obtained are reverse of those of number.

To find:-

• Find the number.?

Solutions:-

• Let the digit at unit's place be 'y'
• Let the digit at ten's place be 'x'

NUMBER = 10x + y

The tens digit of a number is four times it's ones digit.

=> x = 4y ......(i).

If 27 is subtracted from the number digits of the difference obtained are reverse of those of number.

Number obtained by reversing the digits = 10y + x

Original number – 27 = Number obtained by reversing the digits

According to the question:-

=> 10x + y - 27 = 10y + x

=> 10x + y - 10y - x = 27

=> 9x - 9y = 27

=> 9(x - y) = 27

=> x - y = 27/9

=> x - y = 3 .........(ii).

putting the value of 'x' from equation (i) in equation (ii).

=> x - y = 3

=> 4y - y = 3

=> 3y = 3

=> y = 3/3

=> y = 1

Putting the value of 'y' in equation (i).

=> x = 4y

=> x = 4 × 1

=> x = 4

Number = 10x + y

=> 10(4) + 1

=> 40 + 1

=> 41

Hence, the number is 41.