The ten's digit of a number is four times its ones digit. If 27 is subtracted from the number digits of the difference obtained are reverse of those of number. Find the number.
Answers
Given:
The tens digit of a number is four times it's ones digit.
If 27 is subtracted from the number digits of the difference obtained are reverse of those of number.
Find:
The number
Solution:
Let the digit at unit's place be 'y'
Let the digit at ten's place be 'x'
NUMBER = 10x + y
The tens digit of a number is four times it's ones digit.
=> x = 4y ......(i).
If 27 is subtracted from the number digits of the difference obtained are reverse of those of number.
Number obtained by reversing the digits = 10y + x
Original number – 27 = Number obtained by reversing the digits
=> 10x + y - 27 = 10y + x
=> 10x + y - 10y - x = 27
=> 9x - 9y = 27
=> 9(x - y) = 27
=> x - y = 27/9
=> x - y = 3 .........(ii).
putting the value of 'x' from equation (i) in equation (ii).
=> x - y = 3
=> 4y - y = 3
=> 3y = 3
=> y = 3/3
=> y = 1
Putting the value of 'y' in equation (i).
=> x = 4y
=> x = 4 × 1
=> x = 4
Number = 10x + y
=> 10(4) + 1
=> 40 + 1
=> 41
Hence, the number is 41.
I hope it will help you.
Regards.