Question

the ten's digit of a number is twice its unit's digit. the number obtained by interchanging the digits is 36 less than the original number. find the original number.

Answer 1

In a two-digit number,

Let x = the 10's digit

Let y = the units

then

10x+y = the number

:

'ten's digit is twice the units digit."

x = 2y

:

The number formed by interchanging the digits is 36 less than the original number

10y + x = 10x + y - 36

10y - y = 10x - x - 36

9y = 9x - 36

Simplify, divide by 9, results

y = x - 4

From the 1st statement; replace x with 2y

y = 2y - 4

4 = 2y - y

4 = y

then

x = 2(4)

x = 8

84 is the number:

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Answer 2

2x(10) + x(1) = 21x

because 2x is in 10th place and x is in ones place

and by reversing

10x + 2x = 12x

21x - 12x = 36

9x = 36

x = 4

1st no is 2(4) = 8

2nd no is 1(4) = 4

so 84 / 48 is the no

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