Question

The ten's digit of a two digit number exceed it'sunit by 5 . When digits are reversed , the new number added to original number becomes 99 . Find the original number . plzz answer it plzzzzzz

Answer 1

Let the digit in the units place be x

Hence the digit in the tens place is (x + 5)
The original number = 10(x + 5) + x = 11x + 50

Number formed by reversing the digits
= 10x + (x + 5)
= 11x + 5

Given that (11x + 50) + (11x + 5) = 99
⇒ 22x + 55 = 99
⇒ 22x = 99 - 55 = 44
⇒ x = 2

Original number = 11x + 50 = 11(2) + 50 = 72

Hence the original number is 72.

Answer 2

Hi guys,

Let the digit in the units place be x

Hence the digit in the tens place is (x + 5)

The original number = 10(x + 5) + x = 11x + 50

Number formed by reversing the digits = 10x + (x + 5) = 11x + 5

Given that (11x + 50) + (11x + 5) = 99

⇒ 22x + 55 = 99

⇒ 22x = 99 55 = 44

⇒ x = 2

Original number = 11x + 50 = 11(2) + 50 = 72

Hence the original number is 72.

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