The ten's digit of a two digit number is three times the unit's digit. When the digits are reversed, we get 36 less than the number. Find the original number.
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Answer:
62
Step-by-step explanation:
Let say ‘x' is digit on unit's place so 3x is digit on tens' place .
So number is 10*3x+x=31x
Now if reverse the position of digit new number will be
10*x+3x=13x
As given new number is less by 36 from old number
31x-36=13x
18x=36
x=2
So number is 10*3*2+2=62.
Hope this helps you dear!!!
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