Question

the ten's digit of a two digit number is three times the unit's digit. when the digits are reversed we get 36 less than the number find the original number?

Answer 1

Let the one's digit be x and ten's digit be y
then acc to question
       y=3x                  ----------------1
also,
   10y+x=10x+y+36
    9x-9y=-36              ----------------2
from 1 and 2
   9x-9(3x)=-36
   9x-27x=-36
     -18x=-36
          x=2
then also y=3x
               y=3(2)
               y=6

then the no is 10y+x=10(6)+2
                                =62
you can also verify it as 26+36=62

:) Hope this helps!!!!!