The ten's digit of a two digit number is thrice the unit digit. The new number obtained by interchanging the digits is 54 less than the original number . Find the original number
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Answer:
Number is 93
Step-by-step explanation:
Let the digit at unit's place be x.
GIVEN : digit at Ten’s place = 3x
Number formed :
=10 × 3x + x
= 30x + x
= 31x
Number formed after reversing the digits:
=10 × x + 3(x )
= 10x +3x
= 13x
ATQ,
31x -54 = 13x [Given]
31x -13x = 54
18x = 54
x = 54/18
x= 3
Number = 31x = 31 × 3 = 93
Hence, the number is 93.
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