The ten's digit of a two digit number is thrice the unit digit. The new number obtained by interchanging the digits is 54 less than the original number . Find the original number
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Let the number is xy.
x = 3y.
(10x + y) - ( 10y+ x) =54.
9x - 9y = 54.
x -y = 6.
3y -y =6
2y =6
y= 3
x =9.
Original number is = 10 * 9 + 3 =93.
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