Question

The ten's digit of a two-digit number is twice the digit in unit's place. If the ten'digit is made half and its units digit is doubled then the new number obtained
is less than the original number by 27. Find the number,

​

Answer 1

Step-by-step explanation:

$\bf{\underline{\underline\red{Given:-}}}$

• The ten's digit of a two-digit number is twice the digit in unit's place.

• If the ten'digit is made half and its units digit is doubled then the new number obtained
• is less than the original number by 27.

$\bf{\underline{\underline\blue{To\:Find:-}}}$

• The number.

$\bf{\underline{\underline\green{Solution:-}}}$

According to the 1st condition:-

The ten's digit of a two-digit number is twice the digit in unit's place

Let the digit in the unit's place be x

The digit in the tens place is 2x.

The original number

= 10(2x) + x

= 20x + x

= 21x

Therefore:-

The original number = 21x

According to the 2nd condition:-

If the ten's digit is made half.

The ten's digit = $\rm \dfrac{2x}{2}$ = x

If the unit's digit is doubled

The unit's digit = 2x

The resulting number = 10x + 2x = 12x

Given:-

The number obtained is less than the original number by 27

So:-

→ 21x - 12x = 27

→ 9x = 27

→ x = 3

The original number

= 21x

= 21 × 3

= 63

$\underline{\boxed{ \purple{ \rm \therefore The \: original \: number \: = 63}}}$

Answer 2

Answer:

original number 63

new number 36

Step-by-step explanation:

observe each and every step