The ten's digit of two digit number is three times the unit digit. The sum of number and the unit digit is 32. Find the number.
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Answered by
25
Let the two numbers be x and y. If x is the number in the 10th digit and y is the unit digit, then
x = 3y
and 10x+y+y = 32
10x + 2y = 32
and x = 3y. Substituting the value of x in 10x+2y = 32, we get
10 * 3y +2y = 32
or 32y = 32 or y = 1
and x = 3.
Thus, the number is 31.
x = 3y
and 10x+y+y = 32
10x + 2y = 32
and x = 3y. Substituting the value of x in 10x+2y = 32, we get
10 * 3y +2y = 32
or 32y = 32 or y = 1
and x = 3.
Thus, the number is 31.
Answered by
4
Answer:Let the two numbers be x and y. If x is the number in the 10th digit and y is the unit digit, then
x = 3y
and 10x+y+y = 32
10x + 2y = 32
and x = 3y. Substituting the value of x in 10x+2y = 32, we get
10 * 3y +2y = 32
or 32y = 32 or y = 1
and x = 3.
Thus, the number is 31.
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