Question

The ten's place of a three digit number is zero. The sum of the three digits no and the number obtianed by interchanging its digits is 1010. Find the pair of numbers i e original no and no obtianed by interchanging the digits. Is it possible to have more than one pair? If yes write all the pairs

Answer 1

Answer:

Step-by-step explanation:

let say number = 100x + 10y +z

y = 0

100x +z is the number

number by interchanging digits = 100z +x

100x +z + 100z + x = 1010

101x + 101z = 1010

x+z = 10

pair can be

1,9 ,  109 , 901

2,8  208 802

3,7   307 , 703

4,6   406 , 604

5,5   505 , 505

6,4    604 , 406

7,3 , 703 , 307

8,2   802, 208

9,1   901, 109