Question

The tens and ones digit of a two digit number are the same. when the number is added to its reverse, the sum is 88. What is the number.

Answer 1

Hi ,

Let ten's place digit = x

Unit place digit = x

Original number = 10x + x = 11x

According to the problem given ,

11x + 11x = 88

22x = 88

x = 88/22

x = 4

Therefore ,

Required number = 11x = 11 × 4 = 44

I hope this helps you.

:)

Answer 2

Answer:

Let the tens digit be x

Ones digit be x

The number will be 10x+x

And its reverse will be 10x+x

A/q

10x+x +10x+x = 88

22x= 88

x = 88/22

x= 4

therefore the number = 10x+x

10×4+4

40+4

44

Hence the no. is 44

Hope it help you

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