The tens digit in a 2-digit number is 4 more than the digit at the ones place. If the sum of the two digits is 10,
find the number
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let the number on tens place be x and units place be y
so the originol number is 10x+y
y+4=x
x-y=4 [1]
x+y=10 [2]
by adding 1 and 2 , we get
2x=14
so x=7
by puting the value of x in 1 , we get
y=3
so the number is 10*7+3=73
answer is 73
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