the tens digit number of two digit numbers is 4times the units digit.the sum of the oiginal numbers and the numbers obtained by revising the digit is 110,find the number
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let unit digit no be x
and tens digit no be 4x
original no = 10×4x+x=41x
by reversing the no
new no = 10×x+4x=14x
a/q
41x+14x=110
=55x=110
=x=110/55=2
hence original no= 41x=41×2=82
and tens digit no be 4x
original no = 10×4x+x=41x
by reversing the no
new no = 10×x+4x=14x
a/q
41x+14x=110
=55x=110
=x=110/55=2
hence original no= 41x=41×2=82
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