Question

The tens digit of 2 digit number is 3 times the unit digit. The sum of the numbers and the unit digit is 32. Find the numbers.​

Answer 1

Answer:

Let the ones's digit =x

Therefore, tens's digit =3x

Original number =10(3x)+x=31x

Sum of number + unit digit =32

⇒31x+x=32⇒x=1

Tens digit will be 3x=3.

Therefore, the number is 31.

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Answer 2

31

Step-by-step explanation:

=> Let the digit at unit's place be x and the digit at ten's place be y.

=> Required no. = 10y + x

According to question,

=> y = 3x

=> 3x - y = 0 ...(1)

and,

=> 10y + x + x = 32

=> 10y + 2x = 32 ...(2)

Multiplying equation no. (1) by 10

=> 30x - 10y = 0 ...(3)

Now,

Adding equation (3) and (2)

30x - 10y = 0

+ 10y + 2x = 32

32x = 32

x = 32/32 = 1

From (1) we get,

=> y = 3(1) = 3

Required no. is = 10(3) + 1 = 31