Question

the tens digit of a 2-digit number is less than the ones digit by 3 . If the digits are reversed,the difference between the two numbers is 27. If the sum of the digits is11, find the numbers.​

Answer 1

Answer:

The tens digits of a two-digit number is less than the ones digit by 3. If the digits are reversed the difference between the two is 27. If the sum of the digits is 11 what is the number?

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Let X be the 1s digit of a number, X−3 is the 10s digit,

The number is 10(X−3)+X .

Reverse the number so X−3 is 1s digit and X is 10s digits,

Number becomes 10(X)+(X−3)

The SUM of digits is 11 hence

X+(X−3)=11

2X=14

X=7

10s digit=4 , 1s digit=7 , the number is 47.

The reverse is 74 , and 74−47=27 is true.

Step-by-step explanation:

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