Question

the tens digit of a 2-digit number is less than the ones digit by 3 . If the digits are reversed,the difference between the two numbers is 27. If the sum of the digits is11, find the numbers.plzzz follow me​

Answer 1

Answer:

Let XX be the 1s1s digit of a number, X−3X−3 is the 10s10s digit,

The number is 10(X−3)+X10(X−3)+X.

Reverse the number so X−3X−3 is 1s1s digit and XX is 10s10s digits,

Number becomes 10(X)+(X−3)10(X)+(X−3)

The SUM of digits is 1111 hence

X+(X−3)=11X+(X−3)=11

2X=142X=14

X=7X=7

10s10s digit=4digit=4 , 1s1s digit=7digit=7 , the number is 47.

The reverse is 7474, and 74−47=2774−47=27 is true.

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