Math, asked by anupari, 2 months ago

The tens digit of a 2-digit number is less than the ones digit by 3. If the digits are reverse difference between the two numbers is 27. If the sum of the digits is 11, find the number​

Answers

Answered by harshitjaiswal510
0

Answer:

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Answered by Itsmahi001
6

\huge\sf{\underline{\underline{Solution}}}

Let X be the 1s digit of a number, X−3 is the 10s digit,

\sf{The \:  number \:  is  \:  10(x−3)+x .}

Reverse the number so X−3 is 1s digit and X is 10s digits,

\sf{Number  \: becomes   \: 10(x)+(x−3) }

\sf{The \:  Sum \:  of \:  digits  \: is \:   11.}

Hence,

\implies\sf{x+(x−3)=11 }

\implies\sf{2x=14 }

\implies\sf{x = 7 }

10s digit=4, 1s digit=7, the number is 47.

The reverse is 74 , and 74−47=27 is true.

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