Question

The tens digit of a 2-digit number is less than the ones digit by 3. If the digits are reversed , the difference the two numbers is 27. If the sum of the digits is 11, find the number.
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Answer 1

Answer:

47

Step-by-step explanation:

47 is the answer

Let the number be 10a+b  where  a  is the tens digit and  b  is the ones digit. Then we are given three equations:

> b−a=3  

> (10b+a)−(10a+b)=27  

> a+b=11  

Notice that (2) simplifies to  9(b−a)=27  which is the same as (1). One of these is redundant.

Adding (1) to (3) we get  2b=14⇒b=7  and so  a=4  and the number is  47 .

Answer 2

Answer:

Heyy How are you...?????

Step-by-step explanation:

~ Priyanshu