The tens digit of a number is four times its ones digit. If 27 is subtracted from the number, the digits of the difference obtained are reverse of those of the number. Find the number
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Answered by
49
Let us assume x is a tenth place digit and y is one's place digit.
Therefore, the number is 10x + y
Given:
x = 4y ------------1
Also given:
10x + y - 27 = 10y + x
9x - 9y = 27
x - y = 3 ------------2
Substitute the value of x from equation 1 in equation 2
4y - y = 3
3y = 3
y = 1
Therefore, x = 4y = 4 * 1 = 4
The number = 10 * 4 + 1 = 41
Therefore, the number is 10x + y
Given:
x = 4y ------------1
Also given:
10x + y - 27 = 10y + x
9x - 9y = 27
x - y = 3 ------------2
Substitute the value of x from equation 1 in equation 2
4y - y = 3
3y = 3
y = 1
Therefore, x = 4y = 4 * 1 = 4
The number = 10 * 4 + 1 = 41
Answered by
7
Answer:
14
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