The tens digit of a two digit no. is 4 times the units digit. The sum of the no.and the units digit is 42. Find the no.
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Let the digits be x and y
Then the two-digit number is 10x + y
Given: x = 4y ------------1
Now given: 10x + y + y = 42
10x + 2y = 42 -----------2
Substitute the value of x in eqn 2
To get 10 * 4y + 2y = 42
42y = 42
y = 1
Therefore x = 4
The two digit no is 10x + y = 10 * 4 + 1 = 41
Answer: The two digit no is 41.
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