Math, asked by shoaibmalik7687, 11 months ago

The tens digit of a two digit number exceeds its units digit by 6. The number itself is 10 times the sum of its digits. Find the number.

Answers

Answered by josimagic
5

Answer:

The number is 60

Step-by-step explanation:

Let x be the tens digit and y be the units digit

The number can be written as 10x + y

It is given that,

1)The tens digit of a two digit number exceeds its units digit by 6.

  Therefore, x - y = 6  ---------(1)

2) The number itself is 10 times the sum of its digits.

10x + y = 10( x + y)   ------(2)

To find the number

10x + y = 10( x + y)

10x + y = 10x + 10 y

 y = 0

Substituting value of y in (1)

x - y = 6

x = 6

Therefore the number is 10x + y = 10 x 6 + 0 = 60

Answered by bhumikaj65
4

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