Question

The tens digit of a two-digit number is 3 more than the units digit. If you interchange the digits of this two-digit number and add the result to the original number, you get 143. Find the original number.

Answer 1

Step-by-step explanation:

One of the two digits of a two digit number is 3 times the other digit. If you interchange the digits of this two digit number and add the resulting number to the original number, you get 88. What is the original number?

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The answer to the question is ‘26′ or ‘62′.

Let a digit be x (no matter units place or tens digit place) the the other digit will be 3x. Since 3x has to be a single-digit non-zero no. so x can only be either 1,2 or 3.

So the no. is (let it be ‘a’) a= x _3x (Now assuming x to be tens digit..You can also take it as units digit).

Then according to the question:

interchanged no. (let it be ‘b’) b= 3x_x.

now,

a+b=88 ……..(Given)

Since x can only be 1,2 or 3.

so addition would take no carry on.

so a+b=4x_4x=88.

comparing both places:

4x=8

and 4x=8.

(both equations are same)

so x=2.

So no. is either 26 or 62.

You can also see a=10*x+3x=13x

(As a 2-digit no. is of the form 10a+b,where both a,b are single digit no.s ‘a’ not equal to 0. )

similarly b=10*3x+x=31x

a+b=44x=88.

x=2.

so a=26 (or 62 according to what you have taken as tens digit.)

THANK YOU.