Question

The tens digit of a two-digit number is 4 times the digit at one place . If the digit are reserved and the resultant number is added to the original number, then the sum is 110 . Find the original number
I will mark as brainlist if ans is correct ans is 82​

Answer 1

Answer:

82

Step-by-step explanation:

Let one's place number be x

So, ten's place number = 4x

So, Original Number = 10×4x+x = 40x+x = 41x

and Reversed Number = 10×x+4x = 14x

So, 41x+14x = 110

=> 55x = 110

=> x = 2

So, Original Number = 41x = 41×2 = 82

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