Question

The tens digit of a two digit number is 4 times the units digits. The sum of the original number and the number obtained by revising the digits is 110,find the number

Answer 1

let the digit in ones place be x.
then the digit in tens place be 4x.

now,number =10(4x)+x
=40x+x=41x.

if we reverse the digit then the digit in ones place be 4x.
and the digit in tens place be x.
and now,the number=10x+4x=14x.

ATQ
41x+14x=110.
55x=110
x=110/55
x=2.

hence the digit in ones place is 2.
and the digit in tens place is 8.
and number is 8×10+2=80+2
=82

Answer 2

the no. will be 82 after reversing