the tens digit of a two digit number is less by 3 then the unit digit if the product of the two digit are subtracted from the number the result is 15 write the unit digit of the number
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let number be xy...x is tens digit,y is unit digit hence number is 10x+y
Tens digit is less by 3 than unit digit..x=y-3
product of 2 digit is subtracted from number..(10x+y)-xy=15
puy x=y-3 in above equation..
we get quadratic equation.,
y^2-14y+45=0..solving we get y=5,9 hence 2 possible numbers 69 and 25
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