the tens digit of a two digit number is less than the ones digit by 3 if the digits are reversed the difference between the two numbers is 27 if the sum of the digit is 11 find the numbers. step by step explaination.
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Answer: let x be the ones digit of a number, x-3 is the tens digit.
The no is 10(x-3)x
Reverse the no (x-3) is ones digit and x is the tens digit.
10(x) + x-3
The sum of digits is 11 hence,
X+ x - 3 =11
Step-by-step explanation:
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