Question

the tens digit of two numbers is three times the unit digit the sum of the number and the unit digit is 32.find the number ​

Answer 1

Let ten's digit be M and one's digit be N.

The tens digit of two numbers is three times the unit digit.

According to question,

=> M = 3N ___ (eq 1)

The sum of the number and unit digit is 32.

Number = 10M + N

According to question,

=> 10M + N + N = 32

=> 10M + 2N = 32

=> 2(5M + N) = 32

=> 5M + N = 16

=> 5(3N) + N = 16

=> 15N + N = 16

=> 16N = 16

=> N = 16

Substitute value of N in (eq 1)

=> M = 3(1)

=> M = 3

•°• Number = 10M + N

=> 10(3) + 1

=> 31

Answer 2

Answer:

Step-by-step explanation:

$\underline {\bf Given} :-$

The tens digit of two numbers is three times the unit digit.

The unit digit the sum of the number and the unit digit is 32.

$\underline {\bf Solution} :-$

Let the two numbers be x and y.

According to the Question,

x = 3y

⇒ 10x + y + y = 32

⇒ 10x + 2y = 32

Putting x value in 10x + 2y = 32, we get

$\sf \implies 10x + 2y = 32\\\sf \implies 10 \times 3y +2y = 32\\\sf \implies32y = 32\\\sf \implies y = 1\\\bf \implies x = 3.$

Thus, the number is 31.