Question

The tens digits of a certain two-digit number is 1/3 of the units digit. When the digits are reversed, the new number exceed twice the original number by 2 more than the sum of the digits. Find the original number.

Answer 1

the number is 26

Step-by-step explanation:

1/3 of 6=2

and

when digits are reversed,

it's 62

that is twice the original no. and 2 more than sum of its digits(Sum of digits =8)

that is (2*26)+(2+8)

= 52+10

=62

Answer 2

Answer:

26

Step-by-step explanation:

let tens digit be x and units digit be y

number will be 10x+y

x=y/3

3x=y...EQ1

Digits reversed, new number is 10y+x

10y+x=2[10x+y]+[(x+y)+2]

10y+x=20x+2y+x+y+2

10y+x=21x+3y+2

20x-7y=-2...EQ2

From EQ1 and EQ2

x=2

y=6

Number= 10x+y=20+6=26